**Pg. 104 : Question number 11**

The right triangle below has a square attached to its hypotenuse. What is the perimeter of the triangle? Give your answer to the nearest tenth of a centimeter.

√914=30.2

30.2=C²

C²-A²=B²

30.2²-17²=B²

(30x30)-(17x17)=B²

914-289=B²

625=B²

√625=√B²

25=B

A+B+C=permeter

17+25+30.2=perimeter

**72.2=perimeter**

**SORRY THIS IS LATE.**

## 1 comment:

Your formulas are bunched togethe (By the c² and b²) and I find it a bit confusing. Try spacing them up a bit. Isn't 30 x 30 = 900, not 914? Also, since you got some calculations mixed up, your answer is incorrect since

900 - 289 = b²

-14 = b²

Sorry if my comment is a bit confusing, I just tried to explain that your answer is incorrect, and you should re-caluculate.

Post a Comment