Tuesday, January 19, 2010

Alvin's Scribepost for January 19, 2010

For the past century, the north magnetic pole has been drifting across the Canadian Artic. Prior to the 1970's , the magnetic pole was drifting at an average speed of 10 km/year. Since the 1970's , the speed at which the magnetic pole has been drifting has increased to about 50 km/year. The circumference of Earth is approximately 40 000 km.

a) What percent is the current speed of the original speed ?

The Current speed is 50 km/year.
The original speed was 10km /year.

Now to get the percent you first must find the decimal, to do so you first divide 50 by 10 which will give you 5, there's your decimal.
Then you multiply your decimal by 100 so 5 x 100 = 500.
So then the answer is the current speed of the original speed is 500%.

b)The circumference of the earth is approximately 40 000 km. At 50 km/year, what percent of the earth's circumference will the pole drift in 1 year ?.

First we have to find the decimal so then we divide 50 by 40 000, the answer is 0.00125 now we multiply it by 100 to get the percent.
So 0.00125 x 100 = 0.125%
In one year the pole will drift 0.125% of the Earth's circumference

3 comments:

carla841 said...

Nice Job!
Next time you should add color to it and you should use pictures too so your post will stand out. But I liked how you explained everthing.

vanessa 8-41 said...

Good job Alvin ! In between decimal and to do, I don't think you need a comma there. The thing that would've made your scribe post even better is a bit of colour and/or pictures. Other than that.. good job !

Abigail8-73 said...

Good job Alvin! (: It wouldn't have hurt if you put atleast 1 picture and little bit of color too, for the important parts. besides that GREAT JOB! (:

Statcounter

About This Blog

Lorem Ipsum

Calculator





powered by math calculator at calculator.net

  © Blogger templates Psi by Ourblogtemplates.com 2008

Back to TOP